论文代写：化学
在第二组实验中，将化合物与其他类似化合物进行比较。首先对CO3进行了测试。在测试中，溶液中加入了0.1 1m Hcl，并确认反应没有嘶嘶声，所以化合物中没有CO3。其次，对Cl进行了测试，并在此基础上建立了卤素离子的缺失。最后，对KNO3进行了测试，确定了在FeSO4和H2SO4与化合物的交接处形成了一个棕色的环。在这里我们面临一个问题，因为首先棕色的戒指没有出现。因为所有其他的测试都是阴性的，在最后的测试中没有白色沉淀，否定了Cl离子，我们重新做了棕色的环测试。用等量的电抗，我们用蒸馏水把管子与另一根管子进行比较，以找出黑暗的差别，我们将KNO3建立为未知化合物。通过火焰试验确定阳离子为K，通过硝酸盐试验确定阴离子为NO3。
论文代写：化学
In the second set of experiments, the compound was compared to similar other compounds. Firstly, a test for CO3 was conducted. In the test, 0.1M Hcl was added to the solution and it was identified that the reaction did not fizz so there was no CO3 in the compound. Secondly, a test for Cl was conducted and in it the absence of halide ions was established. Finally, the test for KNO3 was conducted and it was identified that a brown ring was formed at the junction of FeSO4 and the H2SO4 mixed with the compound. Here we faced an issue because firstly the brown ring did not appear. Since all other tests were negative, and there was no white precipitate in the last test, negating the Cl ion, we redid the brown ring test. Same amount of reactance was used, and we compared the tube with rung to another with distilled water in order to find out the difference in darkness and we established KNO3 as the unknown compound. The cation is K by flame test and the anion is NO3 by the nitrate test was hence established.
